This circuit was given to me by an instructor at my school and I was told that it can be done with no code violations and with only what is shown on the circuit. I am fairly decent at wiring, which is why he threw this at me for a challenge. Ive looked over for a number of hours and i just cant figure it out. I know i would need to have two switch legs between A and B (one for each switch), the ungrounded conductor to power B and the neutral for light A. I told him this and all he would tell me was its used for conveyor/light circuits all the time and it has a lot to do with kirchoff's law. I understand the law but not how it applies
You say using "Single pole" switch.
Are they SPDT double throw, or SPST single throw ?
You have 2 S1s ?
We have 208v + 208V devices in school and also all the conduit and THHN i could ever want....not sure how it would get me past the whole switching the neutral part of it though.240/208V devices + conduit? You could always pull the neutral later, if needed. That would satisfy the code...
If you make it a 240vac circuit, you do not have a neutral, and you can make it work with simple spst switches. The only issue, and it's 'normal' is that you still have voltage at the lamp fixture, but you are switching only a hot lead.
Jim,
I'm pretty sure you cannot shut off a 240v load with a single pole switch. One needs a two pole switch. Such switches exist. Assuming one has a 240v light bulb fed by opposite hots, one needs to interrupt both hots when shutting it off.
Please don't ask me to cite chapter and verse.
This is awkward, but...
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